Question

Construct a right triangle with. hypotenuse= 13cm and length of a side = 5cm​

Answer 1

GIVEN :-

ABC is an right angled triangle

AC is the hypotenuse => Angle B = 90°

BC = 5 cm

AC = 13 cm

TO CONSTRUCT :- The Triangle ABC

CONSTRUCTION :-

First of all we will find the other side by applying pythagoras Theorem.

${hypotenuse}^{2} = {base}^{2} + {perpendicular \: square}^{2} \\ \\ \implies {13}^{2} = {5}^{2} + {p}^{2} \\ \\ \implies {p}^{2} = {13}^{2} - {5}^{2} \\ \\ \implies p = \sqrt{169 - 25} \\ \\ \implies \boxed{p = 12cm}$

Now, Steps of construction :-

1. Draw base BC of 5cm using ruler and pencil.

2. Construct 90° on point B using protactor.

3.Point A such that AB = 12cm.

4. Join AC.

5. Traingle ABC is constructed .

6. Check that AC= 13cm by scale practically.

Answer 2

Answer:

Step-by-step explanation:

Hi

Hypotenuse=13,length of side=5

By bodhayan theorem

p=√sq of h - sq of b

√ sq of 13-sq of 5

√169-25

√144

12cm