Question

construct a rombus in which measures of the diagnols are 8cm and 6cm.
plzz tell me fasttt plzzzzzzzz​

Answer 1

Answer:

Let Rhombus be PQRS where PR and QS are its diagonals

Steps of construction:

Steps of construction:(i) Draw a line segment PR=8cm

Steps of construction:(i) Draw a line segment PR=8cm(ii) Draw its perpendicular bisector XY intersecting it at O.

Steps of construction:(i) Draw a line segment PR=8cm(ii) Draw its perpendicular bisector XY intersecting it at O.(iii) From XY, cut off OQ=OS=6/2=3cm each

Steps of construction:(i) Draw a line segment PR=8cm(ii) Draw its perpendicular bisector XY intersecting it at O.(iii) From XY, cut off OQ=OS=6/2=3cm each(iv) Join PQ,QR,RS and SP

Steps of construction:(i) Draw a line segment PR=8cm(ii) Draw its perpendicular bisector XY intersecting it at O.(iii) From XY, cut off OQ=OS=6/2=3cm each(iv) Join PQ,QR,RS and SPThus, PQRS is the required rhombus

Answer 2

2.71828

The number e , sometimes called the natural number, or Euler's number, is an important mathematical constant approximately equal to 2.71828.

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