Math, asked by bhavani2000life, 11 months ago

Construct a segment of a circle on a chord of length 5cm. containing the following angles.
(i) 90
(ii) 45
(iii) 120​

Answers

Answered by TanikaWaddle
14

construction

Step-by-step explanation:

Given an angle of 120° and chord 5cm

x + x + 120° = 180°

[using sum of all angles in a triangle = 180°] ⇒ 2x + 120° = 180°

⇒ 2x = 180° - 120°

⇒ 2x = 60°

⇒ x = 30°

steps :

  1. Draw a line segment AB = 5cm
  2. Draw an angle of 30° on point A and B to intersect at O.
  3. With centre ‘O’ and radius OA and OB, draw the circle.
  4. Mark a point ‘C’ under the chord AB and on the arc of the   circle . Join AC and BC.
  5. we get  ∠A0B = 240°.
  6. Thus, ACB is the required circle segment.

similarly,

repeat the same steps for another angles.

hence, ACB is the required circle segment.

#Learn more:

https://brainly.in/question/14995758

Attachments:
Answered by kakumanusreya5
4

Answer:

Answer :

Given an angle of 120° and chord 5cm

Rough Image :

Explanation:

x + x + 120° = 180°

[using sum of all angles in a triangle = 180°]

⇒ 2x + 120° = 180°

⇒ 2x = 180° - 120°

⇒ 2x = 60°

⇒ x = = 30°

Steps of construction:

Step 1: Draw a line segment AB = 5cm

Step 2: Draw an angle of 30° on point A and B to intersect at O.

Step 3: With centre ‘O’ and radius OA and OB, draw the circle.

Step 4: Mark a point ‘C’ under the chord AB and on the arc of the

circle . Join AC and BC.

we get M∠A0B = 240°.

Thus, ACB is the required circle segment

hope it helps

Similar questions