construct a segment of a circle on a chord of length 5cm containing 90°
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Explanation:
x + x + 120° = 180°
[using sum of all angles in a triangle = 180°]
⇒ 2x + 120° = 180°
⇒ 2x = 180° - 120°
⇒ 2x = 60°
⇒ x =
= 30°
Steps of construction:
Step 1: Draw a line segment AB = 5cm
Step 2: Draw an angle of 30° on point A and B to intersect at O.
Step 3: With centre ‘O’ and radius OA and OB, draw the circle.
Step 4: Mark a point ‘C’ under the chord AB and on the arc of the
circle . Join AC and BC.
we get M∠A0B = 240°.
Thus, ACB is the required circle segment.
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