Question

construct a square each of whose sides measure 6cm ​

Answer 1

Step-by-step explanation:

Draw a line AB of 6cm.

From A draw an arc of 180°.

Bisect that angle and extend the line up.

Do the same thing on B.

Keeping the point on A, take the measure of 6cm and cut an arc at D on the extended line.

Do the same thing on B and cut the arc at C.

Join the points where the arcs intersect the line on the top.

The square ABCD is obtained.

Answer 2

Answer:

Given : Diagonal=6 cm.

Steps for construction

Step 1 : Draw the rough diagram and mark the given measures.

Step 2 : Draw a line segment AC=6 cm.

Step 3 : Construct a perpendicular bisector XY of AC.

Step 4 : XY intersects AC at O. We get OC=AO=3 cm.

Step 5 : With O as centre draw two arcs of radius 3 cm cutting the line XY at points B and D.

Step 6 : Join AB,BC,CD and DA.

ABCD is the required square