Question

Construct a square in which Diagonal is 8 cm.

Answer 1

The side of the square a = $4\sqrt{2}$

AB = BC = CD = CA = $4\sqrt{2}$

Step-by-step explanation:

Square ABCD is shown in figure.

Diagonal AC = 8 cm

And each side = a cm

From Δ ABC

$AC^{2} = AB^{2} + BC^{2}$

$8^{2} = a^{2} + a^{2}\\8^{2} = 2a^{2} \\8 = \sqrt{2} a$

a = $4\sqrt{2}$

This is the side of the square.

Since the square have all sides equal so

AB = BC = CD = CA = $4\sqrt{2}$