construct a square parallelogram whose two diagonals are 7.6 cm and 6.2 and the angle between them is 60°
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We know that the diagonals of a parallelogram bisect each other.
So, we may proceed according to the steps given below.
Steps of Construction:
(i) Draw AC = 7.6
(ii) Bisect AC at O.
(iii) Make ∠COX = 70° and produce XO to Y.
(iv) Set off OB = 1/2 (7.6) = 3.8and OD = 1/2 (6.2) = 3.1cm as shown.
(v) Join AB, BC, CD and DA.
Then, ABCD is the required parallelogram
Hope it helps...
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