Question

construct a square STUV the measure of whose diagonal is 8.2cm​

Answer 1

let the side of square = x cm

Using Pythagoras' Theorem

${x}^{2} + {x}^{2} = {(8.2)}^{2}$

$\sqrt{ {x}^{2} + {x}^{2} } = 8.2$

$\sqrt{2 {x}^{2} } = 8.2$

$\sqrt{2} x = 8.2$

$x = \frac{8.2}{ \sqrt{2} }$

$x = \frac{8 .2 \sqrt{2} }{2}$

$x = 4.1 \sqrt{2}$

$x = 5.8 \: cm$