Question

construct a square whose diagonal is 5.2 CM

Answer 1

very easy

the diagonal is 5.2 then let the sides be X

therefore by Pythagoras theorem

x²+x²=(5.2)²

2x²=27.04

x²=13.52

therefore X=3.67.....

by doing this you can construct

but I. will show you a easy method we all know that diagonal of square are the angle bisector

then the angle will be 45°then we can construct the square

there's one more way to construct

draw first line QS of length 5.2 cm

draw a perpendicular bisector on it

mark the point of intersection as O

take the radius of OQ mark two points on the bisector join the line and the square is ready

plz mark it as brainliest ok

sorry for bad pic quality