Math, asked by ravleen732, 1 month ago

construct a square whose each side measures 5.5cm​

Answers

Answered by ayushiprajapati80
0

Step-by-step explanation:

The side of the square is given as 5.5 cm.

Now, we know that a square is a quadrilateral having several properties listed below,

(i) All the sides of a square are equal in length.

(ii) Each angle measures 90 degrees.

(iii) Diagonals AC and BD of a square bisect each other at 90 degrees.

Now let us draw a square ABCD with each side measuring 5.5 cm. Follow the steps for construction.

Step 1: Draw a line segment AB of length 5.5 cm, considering it as a base. Use a ruler to draw the length.

Step 2: Construct perpendicular lines at points A and B with the help of a compass. To do this, place the compass at point A, draw an arc and bisect the angle of 180∘. Do the same for point B. Extend these perpendicular lines.

Step 3: Now, cut a length of 5.5 cm from point A on its perpendicular and mark it as D. Similarly, cut a length of 5.5 cm from point B on its perpendicular and mark it as C.

Step 4: Join C and D, to form a line segment CD, with the help of a ruler to form the square ABCD.

Hence, our construction is complete.

Answered by ksunil15061982
0

Step-by-step explanation:

Step 1: Draw AB=5.5cm

Step 2: Construct 90

o

angles at A and B

Step 3: Taking radius=5.5cm, draw an arc of D and C.

Step 4: Join AD, BC and CD

Hence, ABCD is the required square

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