Question

Construct a square whose one diagonal AC = 7cm.

Answer 1

Step-by-step explanation:

ok it will help to make it

Answer 2

Step-by-step explanation:

Diagonal cuts the squre into two equal right angle triangles. Consider one of them and apply pythagoras theorem

$a^2+a^2=49\\=>a=7/\sqrt{2}$

Therefore the square is of side $a=7/\sqrt{2}$