Question

construct a square with a diagonal of length 8 cm with steps of construction

Answer 1

first draw a AB line segment of a 8 centimetre .
second draw BC which perpendicular bisector of 8 cm.

3 cut the BC lines 4cm from intersection point .

after all join all. ABCD

Answer 2

$ABCD$ is the required Square.

Step-by-step explanation:

Given,

Construct a square with a diagonal of length $8cm$

Diagonal divide any square into two equal wright angle triangle parts.

∴ $2a^{2} =8^{2}$ where $a$ is all sides of square.

⇒$a^{2} =\frac{64}{2}$

⇒$a=\sqrt{32}$

∴ $a=5.65cm$

Following steps:

• Draw a line $BC=5.65cm$ using scale.
• At point $B$ and $C$,draw angle $90$° using protector like $\angle BCY=90$° and $\angle CBX=90$°
• Cuts $BX$ and $CY$ line at $A$ and $D$ with measure $5.65cm$ from point $B$ and $C$
• Join $AD$

Now, $ABCD$ is the required Square.