Question

construct a tangent of the length 4 cm from a point which is at a distance of 5 cm from the centre of the circle​

Answer 1

$\huge\sf{Answer:-}$

According to the given question:-

Construct a tangent of the length 4 cm from a point which is at a distance of 5 cm from the centre of the circle.

Hence,

Given

$\sf = > OB ± AB \\ </p><p>\sf = > OA = 5cm \\ </p><p> \sf = > AB = 4 cm$

Triange ABO

Using Pythagoras Theorem:-

$\sf = > OA2 = AB2 + BO2 \\ </p><p>\sf = > 52 = 42 + BO2 \\ </p><p>\sf = > BO2 = 25 - 16 \\ </p><p>\sf = > BO2 = 9 \\ </p><p>\sf = > BO = 3$

Thence, 3 cm is the radius of the circle.