Construct a tangent to a circle of radius 2 cm from a point on the concentric circle of
radius 5 cm and measure its length. Also verify the measurement by actual
calculation.
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Answer:
Steps of construction are:-
1) Draw a circle of radius 2cm with centre O.
2) Draw a concentric circle of radius 2.6cm centre O.
3) Mark point P on a larger circle.
4) Join PO. Make perpendicular bisector of PO. Let M be a mid point of PO.
5) Taking M as a centre and MO as a radius , draw a circle.
6) Let it intersect the given circle at points Q and R.
7) Join PQ and PR.
Therefore PQ and PR are the required tangents.
Since △PQO is a right angle triangle.
By Pythagoras theorem,
PO
2
=PQ
2
+OQ
2
2.6
2
=PQ
2
+2
2
6.76=PQ
2
+4
PQ
2
=2.76
PQ=1.66
Similarly, PR=1.66
Length of the tangent is 1.66cm.
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