Question

Construct a tangent to a circle of radius of 2 cm from any point R outside the circle.​

Answer 1

Answer:

Since △PQO is a right angle triangle.

By Pythagoras theorem,

PO²=PQ²+OQ²

2.6²=PQ²+2²

6.76=PQ²+4

PQ²=2.76

PQ=1.66

Similarly, PR=1.66

Length of the tangent is 1.66cm.

Step-by-step explanation:

Steps of construction are:-

1) Draw a circle of radius 2cm with centre O.

2) Draw a concentric circle of radius 2.6cm centre O.

3) Mark point P on a larger circle.

4) Join PO. Make perpendicular bisector of PO. Let M be a mid point of PO.

5) Taking M as a centre and MO as a radius , draw a circle.

6)Let it intersect the given circle at points Q and R.

7) Join PQ and PR.Therefore PQ and PR are the required tangents.