Question

construct a tiangle similar to the given trianglr ABC with its sides equal to 5/3 of the corresponding sides of triangle ABC​

Answer 1

ratio of triangles =

ABC : A'BC' = 5:3

Hence,

ABC = 5

A'BC' = 3

Given, a Δ ABC, we are required to construct a triangle whose side are of the corresponding sides of Δ ABC

Construction Steps:

1) Draw any ray BX making an acute angel with BC on the sides opposite to the vertex A.

2) Locate the points B1, B2, B3, B4, B5 on BX such that BB1 = B1B2 = B2B3 = B3B4 = B4B5.

3) Join B3 to C as 3 being smaller and through B5 draw a line parallel to B3C, intersecting the extended line segment BC at C’.

4) Draw a line through C parallel to CA intersecting the extended line segment BA at A’.

Then A’BC’ is the required triangle.