Question

construct a traingle PQR in which QR=7cm,

Answer 1

Answer:

Steps of construction:

• Draw the base QR = 7cm and at the point Q make an angle 75°, say ∠XQR equal to the given angle.
• Cut a line segment QD = 13 cm equal to PQ + PR from the ray QX.
• Join DR and make an angle ∠DRY equal to ∠QDR.
• Let RY intersect QX at P. We constructed required ∆PQR.

Answer 2

Answer:

no

Step-by-step explanation:

sorry I didn't know that answer