Question

construct a traingle PQR PQ=5cm QR=6cm and RP=8.2 and construct circum circle​

Answer 1

Take RP= 8.2cm as the base and with any radius of measurement QR=6cm and cut and arc. Similarly draw for PQ. Then draw perpendicular bisector of line PQ, QR  and PQ . Then we will get a point at the centre. Take a rounder and draw circle placing the needle on the point obtained and the pencil on on any point. the circumcircle is obtained.

Answer 2

Answer:

Step-by-step explanation:

step1-draw a line segment RP=8.2cm

step2-take a compass with radius 5cm and P as centre. Now cut an arc and name it Q

step3-now with radius 6cm and R as centre,draw another arc cutting previous one

step4-join R with Q and P with Q

THIS IS THE REQUIRED TRIANGLE

Triangle PQR