Question

Construct a traingle PQR, with Perimeter of traingle us 11.8cm and Q=60 degree,R=45 degree.​

Answer 1

Answer:

Step 1: Draw a line segment AB of 11cm

Step 1: Draw a line segment AB of 11cmXY+YZ+ZX=11cm

Step 1: Draw a line segment AB of 11cmXY+YZ+ZX=11cmStep 2: Using a protractor mark 30

Step 1: Draw a line segment AB of 11cmXY+YZ+ZX=11cmStep 2: Using a protractor mark 30 ∘

Step 1: Draw a line segment AB of 11cmXY+YZ+ZX=11cmStep 2: Using a protractor mark 30 ∘ at A, i.e ∠PAB and ∠QBA as 90

Step 1: Draw a line segment AB of 11cmXY+YZ+ZX=11cmStep 2: Using a protractor mark 30 ∘ at A, i.e ∠PAB and ∠QBA as 90 ∘

Step 1: Draw a line segment AB of 11cmXY+YZ+ZX=11cmStep 2: Using a protractor mark 30 ∘ at A, i.e ∠PAB and ∠QBA as 90 ∘

Step 1: Draw a line segment AB of 11cmXY+YZ+ZX=11cmStep 2: Using a protractor mark 30 ∘ at A, i.e ∠PAB and ∠QBA as 90 ∘ Step 3: Bisect 30

Step 1: Draw a line segment AB of 11cmXY+YZ+ZX=11cmStep 2: Using a protractor mark 30 ∘ at A, i.e ∠PAB and ∠QBA as 90 ∘ Step 3: Bisect 30 ∘

Step 1: Draw a line segment AB of 11cmXY+YZ+ZX=11cmStep 2: Using a protractor mark 30 ∘ at A, i.e ∠PAB and ∠QBA as 90 ∘ Step 3: Bisect 30 ∘ at A, i.e ∠PAB and ∠QBA at point X.

Step 1: Draw a line segment AB of 11cmXY+YZ+ZX=11cmStep 2: Using a protractor mark 30 ∘ at A, i.e ∠PAB and ∠QBA as 90 ∘ Step 3: Bisect 30 ∘ at A, i.e ∠PAB and ∠QBA at point X. Step 4: Join XZ and make XZ perpendicular to AB.

Step 1: Draw a line segment AB of 11cmXY+YZ+ZX=11cmStep 2: Using a protractor mark 30 ∘ at A, i.e ∠PAB and ∠QBA as 90 ∘ Step 3: Bisect 30 ∘ at A, i.e ∠PAB and ∠QBA at point X. Step 4: Join XZ and make XZ perpendicular to AB.Step 5: Draw perpendicular bisector of AX i.e ST.

Step 1: Draw a line segment AB of 11cmXY+YZ+ZX=11cmStep 2: Using a protractor mark 30 ∘ at A, i.e ∠PAB and ∠QBA as 90 ∘ Step 3: Bisect 30 ∘ at A, i.e ∠PAB and ∠QBA at point X. Step 4: Join XZ and make XZ perpendicular to AB.Step 5: Draw perpendicular bisector of AX i.e ST.Step 6: Mark the point Y where ST and AB intersect. Join XY

Step 1: Draw a line segment AB of 11cmXY+YZ+ZX=11cmStep 2: Using a protractor mark 30 ∘ at A, i.e ∠PAB and ∠QBA as 90 ∘ Step 3: Bisect 30 ∘ at A, i.e ∠PAB and ∠QBA at point X. Step 4: Join XZ and make XZ perpendicular to AB.Step 5: Draw perpendicular bisector of AX i.e ST.Step 6: Mark the point Y where ST and AB intersect. Join XY∴ We get △XYZ

Answer 2

Answer:

ok

Step-by-step explanation:

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