Question

construct a traingle similar to given traingle PQR with it's equal to 2by5 of the corresponding sides of training PQR​

Answer 1

Step-by-step explanation:

1 : Draw a triangle PQR

Step 2 : draw a ray PX with ∠QPX acute angle at P on PQ

Step 3 : Take three points at equal distance on ray PX

Step 4 : join 3rd point with Q

Step 5 : Draw a line parallel to line segment drawn in step 4 passing through 2nd point on PX and intersecting PQ at Q'

Step 6 : Draw a line parallel to QR and passing through Q' and intersect PR at R'

ΔPQ'R' ≈ ΔPQR

ΔPQ'R' side equal to 2/3 of the corresponding sides of the triangle pqr

Learn more:

Draw a triangle ABC with side BC =6.5cm, angle B=30, angle A=105 ...