Construct a trapezium abcd ab parallel to cd where ab 6 cm d 4 cm angle a 70degree angle abd 30 degree
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Answer:
Step-by-step explanation:
Construct a trapezium abcd ab parallel to cd where ab 6 cm d 4 cm angle a 70degree angle abd 30 degree
To draw a trapezium here we should gwt to know the
Height (distance between parallel line)
if We draw perpendicular from shorter side on Longer side
we will form one ractangle 4 * 4
an two triangles with height h & sides x & 2-x
tan 70 = h/x => h = xtan70
tan 30 = h/(2-x) => h =(2-x)tan30
equating this
xtan70 = (2-x)tan30
=> x(tan 70 + tan 30) = 2tan30
=> x = 2tan30/(tan 70 + tan 30)
so
h = 2tan30tan70/(tan 70 + tan 30)
using value of h we can draw a perpendicular from 6 cm line with an height of 4 cm
and draw from there a perpencilar so a line parallel to 6 cm line.
Then From 6 cm line
we can draw angles of 70 & 30 which will cut the already drawn parallel line to form a trapezium.