Math, asked by shafeeq7417, 1 year ago

Construct a trapezium abcd ab parallel to cd where ab 6 cm d 4 cm angle a 70degree angle abd 30 degree

Answers

Answered by Krish3103
23
Sorry for a rough Diagram but this might prove helpful to you
Attachments:
Answered by amitnrw
3

Answer:

Step-by-step explanation:

Construct a trapezium abcd ab parallel to cd where ab 6 cm d 4 cm angle a 70degree angle abd 30 degree

To draw a trapezium here we should gwt to know the

Height (distance between parallel line)

if We draw perpendicular from shorter side on Longer side

we will form one ractangle 4 * 4

an two triangles with height h & sides x & 2-x

tan 70 = h/x     =>  h = xtan70

tan 30 = h/(2-x) => h =(2-x)tan30

equating this

xtan70 = (2-x)tan30

=> x(tan 70 + tan 30) = 2tan30

=> x = 2tan30/(tan 70 + tan 30)

so

h = 2tan30tan70/(tan 70 + tan 30)

using value of h we can draw a perpendicular from 6 cm line with an height of 4 cm

and draw from there a perpencilar so a line parallel to 6 cm line.

Then From 6 cm line

we can draw angles of 70 & 30 which will cut the already drawn parallel line to form a trapezium.

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