construct a trapezium ABCD in which AB//DC A=105 degree AB=4cm CD=8cm and AD=3cm
Answers
Answer:
Step-by-step explanation:
Given:
AB is parallel to DC , BC = 5 cm, CD = 4 cm and AD = 5 cm.
Steps for construction:
Step 1 : Draw a rough diagram and mark the given measurements. Draw
CE ∥ DA
. Now AECD is a parallelogram. ∴ EC = 5 cm, AE = DC = 4 cm, EB = 3cm.
Step 2 : Draw a line segment AB = 7 cm.
Step 3 : Mark E on AB such that AE = 4 cm . [ ∵ DC = 4 cm ]
Step 4 : With B and E as centres draw two arcs of radius 5 cm and let them cut at C.
Step 5 : With B as centre and radius 6 cm draw an arc cutting BY at C.
Step 6 : With C and A as centres and with 4 cm and 5 cm as radii draw two arcs. Let them cut at D.
Step 7 : Join AD and CD . ABCD is the required trapezium.
Step 8 : From D draw DF ⊥ AB and measure the length of DF. DF = h = 4.8 cm, AB = a = 7 cm, CD = b = 4 cm.
Calculation of area. In the trapezium ABCD, a = 7 cm, b = 4 cm and h = 4.8 cm.
Area of the trapezium ABCD = 2 1 h(a+b)
= 2 1 (4.8)(7+4)
= 2 1 × 4.8 × 11
= × 2.4 × 11
=26.4 cm
I HOPE THIS ANSWER WAS HELPFUL , IF YES THEN PLEASE THIS ANSWER IN BRAINLEIST SO THAT I CAN FOLLOW YOU AND ANSWER OTHER QUESTIONS
THANKYOU !
