construct a trapezium ABCD in which ab is parallel to DC and AB =8cm,BC=4cm, CD =3.5cm and DA =4.2cm
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I have drawn rough
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Kaurnimrat:
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★ Here is your answer ★
Given :
- AB||DC
- AB = 8cm
- BC = 4cm
- CD = 3.5cm
- DA = 4.2cm
To do :
- Construction of a trapezium ABCD from the given measures.
Solution:
Step of construction :
- Draw a line of 8cm as AB, and cut off AX = 4.5cm
- Construct the ∆AXD such that XD = 4cm and AD = 4.2cm
- Consider B as center and radius equal to 4cm, draw the arc as C
- Consider D as center as taking radius of 3.5cm, draw am arc which cut at C
- Join BC and DC.
Then, ABCD is required trapezium.
Obtained figure of trapezium :
After given construction, our obtained figure is referred to the attached figure.
Attachments:
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