construct a trapezium Abcd in which one of the parallel side ab =6cm hight =3.5cm bc=4cm and ad=4.7cm
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Answer in the above picture
Step of Construction:-
- Draw a st. line AB=6cm
- Draw a line L || AB at a perp. distance of 3.5 cm
- With A And B as centres,in turn and radii of 4.7cm and 4cm respectively,draw arcs to cut L at D and C
- Join AD and BC
- Then ABCD is the required trapezium
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