Question

Construct a trapezium ABCD ,where AB||DC ,AB=10cm and DC=7cm,AD=5cm and angleA=80°​

Answer 1

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Draw a rough fig. of trapezium ABCD.

Since ABCD is a trapezium and AB|| DC,

you have $\angle{A}$$\angle{D}$=180°

⇉$\angle{D}$=180°-80°=100°

$\Large\bf\underline\red{Steps}$$\Large\bf\underline\red{of}$$\Large\bf\underline\red{Construction:-}$

Step 1:-

Draw line segment AB=10cm

Step 2:-

Using a protractor, construct $\angle{BAX}$=$80°$ at A

Step 3:-

With A as a center and radius = $5cm(=AD)$,draw an arc to cut AX at D.

Step 4:-

Using a protractor, construct $\angle{ADY=100°}$ at D

Step 5:-

With D as center and radius =7cm(=DC),draw an arc to cut DY at C.

Step 6:-

Join BC .ABCD is required trapezium .

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Answer 2

Answer:

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