Question

construct a trapezium ABCD where AB parallel CD AB= 6.5 cm and CD =8.8 cm it's other two sides AD =BC = 3.5 cm ​

Answer 1

Answer:

Given:

AB is parallel to DC, BC = 5 cm, CD = 4 cm and AD = 5 cm.

Steps for construction:

Step 1 : Draw a rough diagram and mark the given measurements. Draw  CE∥DA . Now AECD is a parallelogram. ∴ EC = 5 cm, AE = DC = 4 cm, EB = 3cm.

Step 2 : Draw a line segment AB = 7 cm.

Step 3 : Mark E on AB such that AE = 4 cm .  [ ∵ DC = 4 cm ]

Step 4 : With B and E as centres draw two arcs of radius 5 cm and let them cut at C.

Step 5 : With B as centre and radius  6 cm draw an arc cutting BY at C.

Step 6 :  With C and A as centres and with 4 cm and 5 cm as radii draw two arcs. Let them cut at D.

Step 7 : Join AD and CD . ABCD is the required trapezium.

Step 8 : From D draw DF⊥AB and measure the length of DF. DF = h = 4.8 cm, AB = a = 7 cm, CD = b = 4 cm.

Calculation of area:In the trapezium ABCD, a = 7 cm, b = 4 cm and h = 4.8 cm.

Area of the trapezium ABCD = 21 h(a+b)

=21 (4.8)(7+4)

=21× 4.8 × 11

= × 2.4 × 11

=26.4 cm2