Construct a trapezium MARY where MA || RY and MA = 6 cm
AR = 5.2 cm RY = 3 cm and ZR = 100°.
i want image and steps
Answers
Answer:
Given:
PQ is parallel to SR, PQ = 8 cm, ∠ PQR = 70o QR = 6 cm and PS = 6 cm.
Steps for construction
Step 1 : Draw a rough diagram and mark the given measurements.
Step 2 : Draw a line segment PQ = 8 cm.
Step 3 : At Q on PQ make ∠ PQX whose measure is 70o .
Step 4 : With Q as centre and 6 cm as radius draw an arc. This cuts $$\overline{QX}$$ at R.
Step 5 : Draw RY parallel to OP .
Step 6 : With Q as centre and radius 6 cm draw an arc cutting RY at S.
Step 7 : Join PS . PQRS is the required trapezium.
Step 8 : From S draw ST⊥PQ and measure the length of ST. ST = h = 5.6 cm, RS = b = 6 cm, PQ = a = 8 cm.
Calculation of area:
In the trapezium PQRS, a = 8 cm, b = 3.9 cm and h = 5.6 cm.
Area of the trapezium ABCD = 21 h(a+b)
=21(5.6)(8+3.9)
=21× 5.6×11.9
=33.32 cm2
i hope it will help you
Answer:
This is your answer.
Hope it will help you.
