Question

) Construct a trapezium PQRS in which
PQ = 6.2 cm, QR = 4.2 cm, RS = 3.2 cm,
Q = 75° and PQ || SR.​

Answer 1

Answer:

Here is your answer........!!!!!!!!!!

Step-by-step explanation:

In a trapezoid, PQRS, PQ is parallel to SR,

∴ ∠Q + ∠R = 180°

⇒ 60° + ∠R = 180°

⇒ ∠R = 180° - 75° = 105°

Steps of construction:

Step 1: Draw PQ = 6.2cm.

Step 2: At Q, draw ∠PQX = 105°.

Step 3: From ray QX, cut off QR = 4 cm.

Step 4: At R, draw ∠QRY = 105°

Step 5: From ray RY, cut off RS = 3.2cm.

Step 6: Join SP.

PQRS is the required trapezoid.

i Hope my answer is useful to you....!!!!!!!

Answer 2

Answer:

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Step-by-step explanation:

In a trapezium, PQRS, PQ is parallel to SR,

∴ ∠Q + ∠R = 180°

⇒ 60° + ∠R = 180°

⇒ ∠R = 180° - 75° = 105°

Steps of construction:

Step 1: Draw PQ = 6.2cm.

Step 2: At Q, draw ∠PQX = 105°.

Step 3: From ray QX, cut off QR = 4 cm.

Step 4: At R, draw ∠QRY = 105°

Step 5: From ray RY, cut off RS = 3.2cm.

Step 6: Join SP.

PQRS is the required trapezium