Math, asked by anshisingh152006, 4 months ago

construct a trapezium pqrs in which pq is parallel to sr pq is equal to 6 cm qr is equal to 5 cm ps is equal to 6.5 cm and angle pqr is equal to 60 degree​

Answers

Answered by Anonymous
3

Step-by-step explanation:

Sol: In a trapezoid, PQRS, PQ is parallel to SR, ∴ ∠Q + ∠R = 180° ⇒ 60° + ∠R = 180° ⇒ ∠R = 180° - 60° = 120° Steps of construction: Step 1: Draw PQ = 8cm. Step 2: At Q, draw ∠PQX = 60°. Step 3: From ray QX, cut off QR = 6 cm.

Answered by sonagurjar719
1

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