Math, asked by Rashidkhan9999, 1 year ago

Construct a trapezium PQRS in which PS = 4.7cm, RS= 8 cm, Angle P = 120°, Angle R =45°.

Answers

Answered by Aasthakatheriya1
88
We know in trapezium " Adjacent angles  along the sides are supplementary. So

∠ P  + ∠ S  =  180° , So

∠ S  + 120°  =  180°

∠ S = 60°

Step 1  : Draw a line RS  =  8 cm 

Step 2 : Now take any radius ( Less than half of RS )  and center " R "  draw a semicircle that intersect our line RS at "A " . .....

Step 3 : Join RD that intersect semicircle at " E " . Now with same radius and center " A " and " E " draw arcs these arcs intersect at " F "  . .

Step 4 : Take any radius ( Less than half of RS )  and center " S "  draw an arc that intersect our line RS at " G " .
Step 5 : Take radius of 4.5 cm and center " S "  draw an arc that intersect line SY at " P " .

Step 6 :Take any radius ( Less than half of PS)  and center " P "  draw a semicircle that intersect our line PS at " I " .

Step 7 : Join PK that intersect  our line " RX " at " Q " . We get required trapezium  PQRS.

I hope it help you
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Answered by sparkahope16
8

Answer:

Step-by-step explanation:

draw a rough diagram.

Draw 8cm (RS) using scale.

Using compass, construct 45 degree in the point R.

as, angle P = 120 degree, Angle S is 60 degree( 120+60=180)

Construct 60 degree in point S.

As given PS= 4.7cm, draw 4.7cm from S.

Draw a line from S to P that measures 4.7cm.

connect the line drawn from R to Q.

trapezium is constructed.

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