Question

Construct a triABC in which AB = AC = 5.2 cm and ZA = 120°. Draw AD I BC.​

Answer 1

Answer:

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Answer 2

Step 1 : Draw a line segment BC of length 7cm

Step 2 : Draw an angle of 45o from point B

Step 3 : From Ray AX cut off the line segment BD=1cm

Step 4 : Join C to D

Step 5 : Draw side bisector of DC

Step 6 : Extend side bisector of DC it intersect the Ray BX at point A

Step 7 : Join A to C, ABC is the required triangle.

On measuring, AB=6.1cm,AC=5.1cm