Question

Construct a triangle
A B C in which BC=5.6cm
<B = 30° and the difference between the center
two sides AB-AC = 3cm. please answer I will mark you brainliest​

Answer 1

Answer:

Stepofconstruction

1)DrawthebaseBC=5.6cmandatpointBmakeanangle∠×BC=30  

∘

 

2)CutthelinesegmentBDequalto3cmfromrayBX

3)JoinCDanddrawtheperpendicularbisector,sayPQofCD

4)LetitintersectBXatapointAJoinAC

TheABCistherequiredtriangle.

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Step-by-step explanation: