Question

Construct a triangle
A B C in which BC=5.6cm
<B = 30° and the difference between the center
two sides AB-AC = 3cm​

Answer 1

Step-by-step explanation:

ANSWER

Stepofconstruction

1)DrawthebaseBC=5.6cmandatpointBmakeanangle∠×BC=30

∘

2)CutthelinesegmentBDequalto3cmfromrayBX

3)JoinCDanddrawtheperpendicularbisector,sayPQofCD

4)LetitintersectBXatapointAJoinAC

TheABCistherequiredtriangle.