Question

construct a triangle ABC given BC is equal to 6 CM angle b is equal to 60 degree and a b is equal to 6 CM measure angle A and angle C also then the triangle​

Answer 1

Answer:

Answer:

Step-by-step explanation:

Steps of Construction:

1) Draw a line segment AB = 7 cm.

2) Draw angle ∠ABC = 60° with the help of compass.

3) Cut off BC = 8 cm.

4) Join A and C.

5) The triangle ABC so formed is the required triangle.

i) Draw the perpendicular bisector of BC. The point situated on this line will be equidistant from B and C.

ii) Draw the angle bisector of ∠ABC . Any point situated on this angular bisector is equidistant from lines AB and BC.

The point which fulfills the condition required in (i) and (ii) is the intersection point of bisector of line BC and angular bisector of ∠ABC.

P is the required point which is equidistant from AB and AC as well as from B and C.

On measuring the length of line segment PB, it is equal to 4.5 cm.

Answer 2

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Correct question :

Construct a triangle ABC in which BC=6cm, angle B=60 degrees, and the sum of other two sides is 9cm

Solution :

1. Construct BC = 6 cm
2. Construct an angle of 60° on B
3. Taking Bo as a centre and radius 9 cm, draw an arc which intersect ray of angle 60° at X
4. Join X and C
5. Then draw the perpendicular bisector of XC
6. Wherever this perpendicular bisector intersect, name this as A
7. Join AC

So ABC is the required Δ