construct a triangle ABC given that BC=4.5cm ,<B=60° and AC-AB=1.5cm.
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⇒Construct a line segment BC of 4.5cm
⇒Construct a 45°angle at B
⇒Take the length of PB as 5.6cm.
⇒Join PC
⇒Construct a bisector at PC.
⇒The line will meet BP at point A. Join AC
⇒We get the required triangle.
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hello dear here is your answer
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