Question

construct a triangle ABC in BC =6cm, Angle B=60degree and AB AC=9cm

Answer 1

Solution :-

Step first : Draw a line segment BC = 6 cm.

Step second : construct angle of 60° at B on BC.

Step third : Taking B as centre with 9 cm radius draw an arc which cut the ray of 60° angle at X

Step fourth : join X and c

Step fifth : the draw perpendicular bisector of XC

Step six: wherever this perpendicular bisector intersection BX, name that point as a A

Step seven: Join A and C

Step eight : so ∆ ABC will be the required triangle.

justification :-

AC = AX ( as point A on perpendicular bisector ramains equidistant from X and

AX + AB =9 cm

AC + AB = 9cm

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@GauravSaxena01

Answer 2

Given : triangle abc in which b=60° bc=6cm and ab+ac=9cm  

To Find : construct triangle

Solution:

Step 1: Draw a line segment BC 6 cm.

Step 2 : Draw ∠B =60° using protractor and draw a ray BX.

Step 3 : With Center B and radius 9 cm, make an arc which intersects BX at D.

Step 4 : Join CD

Step 5 : Draw a perpendicular bisector of segment DC it intersect the ray BX at point A.

Step 6 : Join C to A

Triangle is constructed

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