construct a triangle abc in which a 45o b 12o and a+b+c = 10.4 cm
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Step-by-step explanation:
Our question is: Construct a triangle abc if its perimeter is 10.4 cm and two angles are 45 degree and 120 degree.
Let ∠B = 45° and let ∠C = 120° .
Now, in order to represent the triangle ΔABC we need to follow the next steps.
Draw a line segment say XY and equal to perimeter i.e., AB+ BC + CA = 10.4 cm.
Draw ∠LXY = ∠B = 45° and ∠MYX = ∠C = 120°.
Make the bisector ∠LXY and ∠MYX and let them meet at a know point A.
Draw perpendicular bisectors PQ and RS of AX and AY, respectively.
Let PQ intersect XY at B and RS intersect XY at C. Join AB and AC.
Hence, we get the triangle which was asked for.
Hope this helped you!!
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