Question

construct a triangle ABC in which a b + AC = 5.6 CM BC = 4.5 cm and angle B = 45 degree

Answer 1

$\triangle ABC$ is the required triangle.

Step-by-step explanation:

Given,

Construct a $\triangle ABC$ in which $AB+AC=5.6\ cm$,$BC=4.5\ cm$ and $\angle B =45\ degree$

Following steps:

• Draw a line segments $BC=4.5\ cm$ using scale.
• At $B$, draw angle $45\ degree$ using protector like $\angle CBX=45\ degree$
• Cuts a point $Y$ on line $BX$ like $BY=5.6\ cm$ ($AB+AC=5.6\ cm$)
• Join $CY$

• Bisect the line $CY$ which cuts at point $A$

• Join $AC$

Now, $\triangle ABC$ is the required triangle.

Answer 2

Given that:-

In Δ ABC,

AC = $5.6$cm BC = $4.5$cm and angle B = $45^o$

We have to construct the triangle ABC by given parameters,

Steps for constructing the triangle ABC,

=> Step 1: Draw a $BC =4.5$ cm line segment. 

=> Step 2: Draw ∠XBC = $45^o$ at point B. 

=> Step 3: Draw an arc with a radius of $5.6$cm that intersects XB at point D from point B. 

=> Step 4: Join $DC$,

=> Step 5: Construct a perpendicular bisector of DC that passes through A and intersects DB. 

=> Step 6: Join $AC$, As a result, the needed triangle is ABC.