Construct a triangle ABC in which AB=3.6cm , BC=4.4 cm and median BE =3 cm
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Step-by-step explanation:
To construct a triangle ABC in which AB = 3.6 cm, AC = 3.0 cm and BC = 4. 8 cm, use the following steps.
1.Draw a line segment BC of length 4.8 cm.
2.From B, point A is at a distance of 3.6 cm. So, having B as centre, draw an arc of radius 3.6 cm.
3.From C, point A is at a distance of 3 cm. So, having C as centre, draw an arc of radius 3 cm which intersect previous arc at A.
4.Join AB and AC. Thus, ΔABC is the required triangle.
Flere, angle B is smallest, as AC is the smallest side. To direct angle B, we use the following steps.
1.Taking B as centre, we draw an are intersecting AB and BC at D and E, respectively
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