Question

Construct a triangle ABC in which AB = 3.8 cm,

Answer 1

Answer:

ok

Step-by-step explanation:

Construct line segment AC = 2.6 cm Considering A as centre and radius 3.8cm, construct an arc Considering C as centre and radius 5cm, construct an arc which intersects the previous arc at the point B Join the points AB and BC So we get △ ABC From the figure we know that BC is the largest side of the triangle BC = 5cm We know that ∠A is the largest angle Considering A as centre and any radius, construct and arc which intersects AB at point P and AC at point Q Considering P as centre and radius more than half of PQ, construct an arc Considering Q as centre and same radius, construct an arc intersecting the previous arc at the point R Join AR and extend it Therefore, ∠A is bisected by the ray AR.Read more on Sarthaks.com - https://www.sarthaks.com/728134/construct-a-abc-in-which-bc-5cm-ab-3-8cm-and-ac-2-6cm-bisect-the-largest-angle-of-this-triangle. These are steps

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Answer 2

Step-by-step explanation:

1.draw a line of 3.8 cm with a scale and name it as A and B.

2. Take a compass of sum measure and keep it on point A and mark at above line A and B .

3)Now take the same measure in the compass and keep it on point B and intersect the other mark and draw the line from Aand B at intersecting point and name it as point C .

4.Triangle ABC is formed