Math, asked by sanjitkumartirkey200, 5 months ago

construct a triangle ABC in which AB=4cm ,BC=5cm,and AC=6cm. then construct another triangle whose sides are 2/3 times the corresponding sides of triangle ABC​

Answers

Answered by Anonymous
0

Answer:

ANSWER

Steps:

1. draw base AB=4cm

2. with A as center, with a scale of 5cm as radius draw an arc and with B as center, with a scale of 6cm as radius draw an arc.

3. let C be the point of intersection of the above 2 lines.

4. draw a ray AX making an acute angle with line AB on the opposite side if the vertex C.

5. mark 3 points A1,A2,A3 such tha A1A2=A2A3=A3A1

6. join A3B and draw a parallel line B

A2

7. draw a line parallel to BC to intersect AC at C

Thus AB

C

is a required triangle.

Justification;

By construction,

AB

AB

=

AA3

AA2

=

3

2

also B

C

∥BC

∴∠AB

C

=∠ABC

In △AB

C

,△ABC

∠A=∠A

∠AB

C

=∠ABC

△AB

C

∼△ABC

AB

AB

=

AC

AC

=

BC

B

C

AB

AB

=

AC

AC

=

BC

B

C

=

3

2

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