Math, asked by durga261, 4 months ago

construct a triangle ABC in which AB = 5.1 cm, m angle QPR = 45° and m angle PQR 85°​

Answers

Answered by mokshyadav53
1

Step-by-step explanation:

1 . take a line Ab of 5.1cm


mokshyadav53: bye
KANAKPHALET: to jaana
mokshyadav53: chup hoja
KANAKPHALET: awwwwwwwwwwwwwww piggyy ko gussa aaya
mokshyadav53: chal unfollow kr jlde se
mokshyadav53: tere follow ki zarurat hi nhi
mokshyadav53: chamkadar si
mokshyadav53: chipkali
mokshyadav53: guu kha jaa ke
mokshyadav53: nikal
Answered by KANAKPHALET
2

Answer:

To construct: A line, parallel to given line by using ruler and compasses.

Steps of construction:

(a) Draw a line-segment AB and take a point C outside AB.

(b) Take any point D on AB and join C to D.

(c) With D as centre and take convenient radius, draw an arc cutting AB at E and CD at F.

(d) With C as centre and same radius as in step 3, draw an arc GH cutting CD at I.

(e) With the same arc EF, draw the equal arc cutting GH at J.

(f) Join JC to draw a line l.

This is the required line AB || l.

Attachments:

KANAKPHALET: i gotta go for lunch
KANAKPHALET: will catch you up at 3:40PM
mokshyadav53: I am fine
mokshyadav53: oh I see
mokshyadav53: ok
mokshyadav53: bye
mokshyadav53: hi
mokshyadav53: I think I like you
mokshyadav53: hi
KANAKPHALET: whatever
Similar questions