Construct a triangle ABC in which AB=5.8cm, BC+CA=8.4cm and angle B is 60 degree . Also justify your answer
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Constructing triangle ABC in which AB = 5.8 cm , BC + CA = 8.4 cm and ∠B = 45°.
Step 1: Draw a line segment AB 5.8 cm.
Step 2 : Draw ∠B = 45°.
Step 3 : With Center B and radius 8.4 cm, make an arc which intersects BX at D.
Step 4 : Join D to A.
Step 5 : Draw a perpendicular bisector of segment DA it intersect the line segment BD at point C.
Step 6 : Join C to A.
ABC is the required triangle.
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Step 1: Draw a line segment AB 5.8 cm.
Step 2 : Draw ∠B = 45°.
Step 3 : With Center B and radius 8.4 cm, make an arc which intersects BX at D.
Step 4 : Join D to A.
Step 5 : Draw a perpendicular bisector of segment DA it intersect the line segment BD at point C.
Step 6 : Join C to A.
ABC is the required triangle.
If it's work then follow me for more answer
KrishnaSir:
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First take AB as the base , then construct angle b as 60 degrees, then on the ray, take a measure of 8.4 , mark it X, then join x to b, construct a perpendicular bisector for XB, mark the point of intersection at ray AX , mark the point of intersection as C , join A to C, your triangle is constructed. Measure BC and CA, add them, if you get your answer as 8.4cm then it's justified and mention it in a paper.
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