construct a triangle ABC in which AB = 5 cm angle B= 60 degree altitude CD =3 cm construct a triangle AQR similar to triangle ABC such that side of a triangle AQR is 1.5 Times that of the corresponding sides of triangle ACB
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●Draw a line segment AB of length 5cm.
Taking B as point Construct an angle of measure 60° using a compass.
●Name the angle as angle ABX.
●Draw a line EF at a height of 3 cm such that it is parallel to the line segment AB. It must intersect ray BX at point C. Now join AC.
●Draw CD perpendicular to AB. CD is altitude of triangle ABC having height 3cm.
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