Question

Construct a triangle ABC in which AB = 5 cm, BC = 4.7 cm and AC = 4.3 cm.

Answer 1

Construction steps :

1 ) Draw a line segment AB = 5cm.

2 )With A and B as a centers and radii

4.3 cm and 4.7 cm draw two arcs which

intersects each other at C .

3 ) Join C to A and B .

∆ABC is formed with given measures.

••••

Answer 2

Take base BC = 4.7cm

Take B as centre and and draw an arc above the BC with rounder measuring 5cm

Now
Take C as centre and draw an arc above BC with rounder measuring 4.3 cm

We get a point A

Hence join AB and AC

Hence
ABC is the required triangle