Math, asked by StarTbia, 1 year ago

Construct a triangle ABC in which AB = 5 cm, BC = 5 cm and AC = 4.3 cm.

Answers

Answered by mysticd
8
Given :

In ∆ABC , AB = 5cm , BC= 5cm ,

AC = 4.3 cm

Construction steps :

1 ) Draw line segment AB = 5 cm.

2 )Take A , B as centres and 4.3 cm

and 5 cm radii draw two arcs which

intersects each other at C .

3 ) Join C to A and B .

Required ∆ABC is formed.

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Attachments:
Answered by BloomingBud
2
Take base BC = 5cm

Take B as centre and and draw an arc above the BC with rounder measuring 5cm

Now
Take C as centre and draw an arc above BC with rounder measuring 4.3 cm

We get a point A

Hence join AB and AC

Hence
ABC is the required triangle
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