Construct a triangle ABC in which AB = 5 cm, BC = 5 cm and AC = 4.3 cm.
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Answered by
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Given :
In ∆ABC , AB = 5cm , BC= 5cm ,
AC = 4.3 cm
Construction steps :
1 ) Draw line segment AB = 5 cm.
2 )Take A , B as centres and 4.3 cm
and 5 cm radii draw two arcs which
intersects each other at C .
3 ) Join C to A and B .
Required ∆ABC is formed.
••••
In ∆ABC , AB = 5cm , BC= 5cm ,
AC = 4.3 cm
Construction steps :
1 ) Draw line segment AB = 5 cm.
2 )Take A , B as centres and 4.3 cm
and 5 cm radii draw two arcs which
intersects each other at C .
3 ) Join C to A and B .
Required ∆ABC is formed.
••••
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Answered by
2
Take base BC = 5cm
Take B as centre and and draw an arc above the BC with rounder measuring 5cm
Now
Take C as centre and draw an arc above BC with rounder measuring 4.3 cm
We get a point A
Hence join AB and AC
Hence
ABC is the required triangle
Take B as centre and and draw an arc above the BC with rounder measuring 5cm
Now
Take C as centre and draw an arc above BC with rounder measuring 4.3 cm
We get a point A
Hence join AB and AC
Hence
ABC is the required triangle
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