Question

Construct a triangle ABC in which AB=5cm.Angle B=60° altitude CD=3cm . Construct a triangle AQR similar to triangle ABC such that side of triangle AQR is 1.5 times that of the corresponding sides of triangle ABC.

Answer 1

1. Draw a line segment AB of length 5 cm .
2. From B, cut an arc of radius 6 cm.
3. With center A , draw an arc of radius 7 cm intersecting the previously drawn arc at C.
4. Join AC & BC to obtain the desired triangle.
5. With center B & radius more than half of BC, draw two arcs on both sides od BC.
6.With center C and the same radius as in the previous step, draw two arcs intersecting the arcs drawn in the previous step at X & Y.
7. Join XY to get the perpendicular bisector of BC.......
HOPE THIS HELPS YOU ANNA.....