Question

construct a triangle ABC in which AB=5cm,<A=60°,BC+AC=9.8cm.write the steps of construction​

Answer 1

Answer:

Steps:

1. Draw AB of 5cm

2. With B as a centre construct 60°and extend the ray BX

3. On ray BX mark an arc of 9.8cm at Y

4. Draw perpendicular bisector of ray BY meeting on BX at C

5. Join AC

Therefore, ABC is the required triangle.

Answer 2

Steps:

1. Draw AB of 5cm...
2. With B as the centre construct 60° and extend the ray BX.
3. On ray BX mark an arc of 9.8 cm at Y
4. Draw perpendicular bisector of ray BY meeting on BX at C.
5. Join AC

Therefore, ABC ; the required angle is constructed... :)

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