∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆Construct a triangle ABC in which AB=7.2cm,BC=8.0cm and AM(median to side BC)=4.5cm
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◆Ekansh Nimbalkar◆
hello friend here are the steps of construction
1)Draw a line segment BC=8.0cm
2)Draw EF,the perpendicular bisector of BC and let it intersects BC at M
3) With centre M and radius=4.5,draw an arc
4)With centre B and radius equal to 7.2cm,draw another arc ,cutting the previous arc at A
5)Join AB and AC
Then,∆ABC is the required triangle
He
hello friend here are the steps of construction
1)Draw a line segment BC=8.0cm
2)Draw EF,the perpendicular bisector of BC and let it intersects BC at M
3) With centre M and radius=4.5,draw an arc
4)With centre B and radius equal to 7.2cm,draw another arc ,cutting the previous arc at A
5)Join AB and AC
Then,∆ABC is the required triangle
He
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