Question

construct a triangle ABC in which AB + AC = 10 cm and angle angle A = 45° also write the steps ( its urgent)​

Answer 1

Step-by-step explanation:

Draw base BC of length 10 cm.

Now, let's draw ∠B=45. ∘ .Let the ray be BX.

Open the compass to length AB−AC= 5cm. Since AB−AC=5cm is positive. ...

Join CD.

Now, we will draw perpendicular bisector of CD.

Mark point A where perpendicular bisector intersects BD.

Join AC.